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Posted: Tue Nov 28, 2006 4:50 pm
Alrighty. I am taking Calc this year and having a bit of trouble with it. I find it confusing. I was hoping that someone could help explain some of the principles to me. If you need math help yourself, just post the problem or problems and I will see what I or someone else can do for you.
I realized that since I am trying to do this online, we should get some common symbols down. Here are a few:
Pi - 3.1415... e - 2.7182... i - imaginary number (result of radical -1) Radical - write as root x Radians - rad Degrees - deg Exponent - ^(x) Division - (x/y) Multipication - (x*y) , (xy) , (x)(y) Derivative - dy/dx , f'(x)
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Posted: Tue Nov 28, 2006 4:57 pm
reserved for current problems. If you have a problem that you need help with, put it in one of the gold border thingies to make it easier to find. Thanks!
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Posted: Wed Nov 29, 2006 2:16 pm
eek I wish I could help xp . Sorry sweatdrop .
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Posted: Wed Nov 29, 2006 3:43 pm
Whoa, whoa, what?
I'm in Calculus as well, and.. you must be farther than me. Because we never learned maxes and mins. You don't by chance mean the limits as x approaches positive and negative infiniti, do you?
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Posted: Wed Nov 29, 2006 5:15 pm
0xA=0 True 0xB=A False
0x8=0 but 0xB=/=A
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Posted: Wed Nov 29, 2006 7:02 pm
KumarKakarla Whoa, whoa, what? I'm in Calculus as well, and.. you must be farther than me. Because we never learned maxes and mins. You don't by chance mean the limits as x approaches positive and negative infiniti, do you? Past that. Have you done derivatives yet? Apparently this is a step or two before finding the area under a curve and that kind of fun stuff. xp My current problem is figuring out how to find the maxes and mins of a derivative of a function within a certain range. We were given: If f(c) is a max or min, then f'(c) = 0 or f'(c) is undefined. The converse is not true. Counter example would be a ledge. Critical Points -> let f be defined at c. If f'(c) = 0 or f'(c) is undefined, then c is a critical number of f. Extrema -> let f be defined on an interval (I) containing c 1.) f(c) is the absolute max of f provided f(c) > f(x) for all x's in I 2.) f(c) is the absolute min of f provided f(c) < f(x) for all x's in I In order to find extremas we must find the critical points then test the critical and end points. Can someone explain this to me in plain english? I just don't get it. How can there be a max and min for a line? or for a curve with multiple fluxuations, like a sine curve? I am so cunfuzzled
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Posted: Wed Nov 29, 2006 7:03 pm
Reesane 0xA=0 True 0xB=A False 0x8=0 but 0xB=/=A Wha-?
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Posted: Wed Nov 29, 2006 8:22 pm
Oh gosh. I wish I wasn't in stupid math anymore. D: So sad that I dropped from math honors level. Quote: 0xA=0 True 0xB=A False 0x8=0 but 0xB=/=A Those look like smileys.
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Posted: Wed Nov 29, 2006 8:57 pm
yeah....I guess no one can help you. I'm new here by the way. Sorry, I was one of the ones who answered will never take calc. I struggled through high school algebra. Love writing though. Need any Spanish tutoring?
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Posted: Thu Nov 30, 2006 11:26 am
We recently went over that in my calculus class, so I can help ya out, but give me some time to get it together first. I'll post again when I get it.
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Posted: Thu Nov 30, 2006 12:10 pm
hmm.. i have only a skeletal knowledge of calculus... but, from what i can decipher... it seems like you dont understand what a max/min is...
in its simplest form, a maximum... either local or absolute) is a point where all the points surrounding it are lower. so, on a sine graph, like you mentioned, every point at the top of a crest isa local maximum. similarly, every point at the bottom of the trough of a sine graph is a local minimum.
i think you have to find the derivative of of the function f... and then use value c in both the original function, and the derived function.
the only thing i know about derivatives is that
if f(x) = x^(3) + 2x^(2) + 4... the derivative is... f'(x) = 3x^(2) + 4x according to the format nx^(n-1) mind you... i dont really maintain that anything i say is correct... i only took a calc 101 class for academic decathlon this year. so, i only have about four hours worth of crash course calc...
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Posted: Thu Nov 30, 2006 12:27 pm
First of all, I tend to explain things in such a way that people... don't usually follow well sweatdrop , so if I'm terribly confusing, just let me know and I'll try to explain differently. Second, the following information is specifically for curves within a limited domain. When they talk about have maximums and minimums they are talking about in a small area unless they talk about absolute or global ones. Absolute or global means that those are the max or min values for the WHOLE graph within your domain. Relative maxes and mins occur within a smaller area of the curve inside your domain, a matter of one point being higher or lower than the two points on either side. For example, on a sine curve, EACH time the curve gets to its highest point, that is the relative max for that area and it goes the same way for mins. Also, if you have a curve that goes up to y=3, back down somewhere, and then back up to y=5, both 3 AND 5 are relative maxes; 5 would be the absolute max here. Quote: If f(c) is a max or min, then f'(c) = 0 or f'(c) is undefined. The converse is not true. That is saying that whenever you have a max or min in the function, the value of the derivative of the function at that point will be 0 or undefined exclaim but NOT indeterminate exclaim In case you don't know, undefined is when a rational is some number over 0, like 4/0. Indeterminate is when a rational is 0/0. The converse part is saying that just because f'(c)=0 or is undefined it does not mean that you have a max or min there, so you have to test the points that you find. I think this post is long enough for now... Let me know if you need more help or if any of this confuses you more or whatever.
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Posted: Thu Nov 30, 2006 12:30 pm
WoW eek I feel kinda stupid now... First, I finished my post AFTER someone else already answered... and ProphetSarcomeer only took a few hours of Calc and understands it quite well! And you explain a lot better too!
Well, at least we aren't saying anything opposing... heh. sweatdrop
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Posted: Thu Nov 30, 2006 1:49 pm
chronohart WoW eek I feel kinda stupid now... First, I finished my post AFTER someone else already answered... and ProphetSarcomeer only took a few hours of Calc and understands it quite well! And you explain a lot better too! Well, at least we aren't saying anything opposing... heh. sweatdrop Actually, you explained what I needed to hear. I already knew the max and min stuff, just not why I needed to test them. Thank you both.
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Posted: Fri Dec 01, 2006 1:02 am
Nice, a calc thread xd I'm taking first year university calc right now, and it gets so much harder than that. I've got an exam coming in about a week though. Glenlyon My current problem is figuring out how to find the maxes and mins of a derivative of a function within a certain range. We were given: If f(c) is a max or min, then f'(c) = 0 or f'(c) is undefined. The converse is not true. Counter example would be a ledge. Critical Points -> let f be defined at c. If f'(c) = 0 or f'(c) is undefined, then c is a critical number of f. Extrema -> let f be defined on an interval (I) containing c 1.) f(c) is the absolute max of f provided f(c) > f(x) for all x's in I 2.) f(c) is the absolute min of f provided f(c) < f(x) for all x's in I In order to find extremas we must find the critical points then test the critical and end points. Can someone explain this to me in plain english? I just don't get it. How can there be a max and min for a line? or for a curve with multiple fluxuations, like a sine curve? I am so cunfuzzled sweatdrop I know other people have already answered this, but here goes anyway.... xd I think they mean a curve - otherwise the derivative for a line would be constant - e.g. y = 4x + 9 --> y' = 4. If it's a curve, for example say a parabola y = x^2, then y' = 2x. When y' = 0 (in this case it can't be undefined because there's no value you can sub in for x to make it undefined), x = 0. This means that (0,0) is a minimum. Basically take f(x) as like a machine. If you pop in the number "x", it'll give you some result. If you pop in the number "c", it'll be higher than any number you can get when you use "x". This means that since f(c) will give you the highest number out of all possible numbers, which is why it'll be a maximum. For a minimum it's the exact opposite. As for local maxes/mins and absolute maxes/mins, "local" means "within an interval". If you set the interval to be only between say a and b then any point higher or lower won't count. If it's absolute max/min, then it means for any value at all that is defined. It's asking you to also check the endpoints because it's quite possible that that's where the local max/min is. Some notations for you: (x,y) -> round brackets mean "open interval" [x,y] -> square brackets mean "closed interval" This is the "shorthand" for defining an interval. Hope that helps =) Feel free to ask if you need any help 3nodding
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