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nonameladyofsins

PostPosted: Tue Jun 27, 2006 12:26 pm


So, I was wondering; I realize that Einstein tried to picture what it would be like from the point of view of the photon, and as he went faster, the photon did not go any slower. I also realize that the speed of light is the same in all inertial reference frames. If the speed of light is always c no matter how fast you are going (compared to other intertial reference frames) then cannot it be concluded that you are always at rest in the intertial reference frame of light? Can't we say that from the point of view of light, everything else is at rest?

Also, people always say that in non-inertial reference frames it's different, how is it different? What changes?
PostPosted: Tue Jun 27, 2006 3:37 pm


The problem is, photons don't observe time as passing, so everything happens at the same time, so speed doesn't really mean anything to a photon. One could try to say that relative to a photon, everything is moving at the speed of light, but it's an inherently broken notion, because a frame moving at the speed of light is not a possible reference frame.

The thing about non-inertial reference frames is that you can tell that you are accelerating, because the laws of physics don't remain quite the same. You get all sorts of fictious forces, such as gravity and the like.
It's kinda like how when you're spinning, you feel a "centrifugal" force, but that's not actually a force, that's just inertia coupled with your acceleration.

Layra-chan
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VorpalNeko
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PostPosted: Tue Jun 27, 2006 5:39 pm


This is exactly why I need to get back to writing the intro to str. Here's a quick summary of the deal. My apologies that this take the time to explain things fully, but I hope you have enough familiarity with these concepts that it will do.

In Euclidean (x,y)-space, the metric is ds² = dx²+dy², which is just the Pythagorean theorem or distance formula in differential form. Rotations about the origin preserve the distance from the origin. Curves of constant distance r from the origin are {r² = x²+y²}, which are circles--this is taken directly from the metric. Thus, rotations in Euclidean space translate points along these curves--they "go around in circles", if you will.

The Minkowski metric is ds² = dt²-dx². The curves of constant r from the origin are {r² = t²-x²}, why are now hyperbolas (familiarity with conic sections helps a lot here). Rotations in Minkowski spacetime translate points along hyperbolas instead of circles. These rotations are called Lorentz boosts, and they inertial reference frames that share an origin (if a translation of is also involved, they are known as Poincaré transforms). Now, hyperbolas have asymptotes--in these case, the asymptotes are t = ±x, which represent the speed of light. This is critical: since they are asymptotes, no amount of rotation (Lorentz boost) will reach these points.

Immediately, it follows that no amount of acceleration (Lorentz boost) will allow one to reach lightspeed. Their complete disconnect from every inertial frame means that they are not proper inertial frames at all--i.e., light has no inetial reference frame. It doesn't make much sense to talk about how the universe "looks" from the "point of view" of a light beam.

By considering constant rotation in Euclidean coordinates (in a circle), one can also derive constant rotation (acceleration!) in Minkowski spacetime, since they are related by a Wick rotation (here, x→ix), which will be again by along a hyperbola. If the particle being accelerated is far enough away, its hyperbolic wordline will be below the line t = x--in other words, there will be an horizon preventing an observer at the origin from sending signals to that particle (but not vice versa).

Yes, there are event horizons in special relativity. The difference in GTR is that some event horizons are no longer observer-dependent--they're absolute.
PostPosted: Tue Jun 27, 2006 6:08 pm


Alright, I totally almost kept up with that until the second-to-last paragraph. How is the distance from the origin in Minkowski space telling us its worldline?

Swordmaster Dragon


nonameladyofsins

PostPosted: Tue Jun 27, 2006 7:58 pm


yeah everything was fine, but I also lost you at the second last paragraph, explain in more depth please. I didn't understand very much in that paragraph at all.
PostPosted: Tue Jun 27, 2006 8:45 pm


If you need me to clarify a specific statement, please quote it so I'll know where exactly I'm losing you.
poweroutage
yeah everything was fine, but I also lost you at the second last paragraph, explain in more depth please. I didn't understand very much in that paragraph at all.

The second paragaph counting or not counting the introductory one? I'll just start from the beginning, adding more details. Alright. The analogy is pretty simple. The Euclidean metric ds² = dx²+dy². It is directly related to the Pythagorean theorem and distance formula. Recall the standard distance formula
s = sqrt[(x1-x2)²+(y1-y2)²], or s² = Δx² + Δx²,
where Δ represents "change in": the square of the distance is the sum of squares of the changes in x- and y-coordinates. The Euclidean metric is just the differential form of this.

Take a point and rotate it around the origin, say counterclockwise. What do you get? A circle. Note that the rotation does not change the distance from the origin--this property can be used to define rotations. In Euclidean space, circles satisfy an equation in the form r² = x² + y². Note the direct connection with the metric.

Now, what would a rotation in Minkowski spacetime look like? Well, it should keep the same distance from the origin. How does one calculate distance? Well, the metric is ds² = dt²-dx². Or:
s² = Δt² - Δx², or s² = (t1-t2)² - (x1-x2)².
[Note: Obviously, s² can be negative, and thus have imaginary distance s. In that case, we call the points "spacelike" relative to one another.]
The corresponding curve of constant distance r is then r² = t²-x². This is a hyperbola. Again, note the direct connection with the metric.

Euclidean--rotations go along circles (constant distance curves in Euclidean space)
Minkowski--rotations go along hyperbolas (constant distant curves in Minkowski spacetime)

Are you alright so far?

Swordmaster Dragon
Alright, I totally almost kept up with that until the second-to-last paragraph. How is the distance from the origin in Minkowski space telling us its worldline?

Let's say the object starts out at (t,x) = (0,d) and is accelerated at a constant rate. Its wordline will be traced out by a constant rotation of the vector [0;d]. As I've mentioned prior to this, rotations produce hyperbolic curves in Minwkoski spacetime. The resulting hyperbola has vertex at (0,d), and it is possible for it to be completely below the line t = x [t>0], which corresponds to a light signal from the origin. In that case, no light signal sent at any t>0 will reach the object (i.e., intersect the worldline).

VorpalNeko
Captain


nonameladyofsins

PostPosted: Tue Jun 27, 2006 9:48 pm


VorpalNeko

If you need me to clarify a specific statement, please quote it so I'll know where exactly I'm losing you.


I mean the second last paragraph in your post. here:

VorpalNeko

By considering constant rotation in Euclidean coordinates (in a circle), one can also derive constant rotation (acceleration!) in Minkowski spacetime, since they are related by a Wick rotation (here, x→ix), which will be again by along a hyperbola. If the particle being accelerated is far enough away, its hyperbolic wordline will be below the line t = x--in other words, there will be an horizon preventing an observer at the origin from sending signals to that particle (but not vice versa).


So now I don't understand what the rotation in Euclidian coordinates and t constant rotation in Minkowski spacetime is. I understand the whole hyperbola thing and the equations for spacetime.
PostPosted: Tue Jun 27, 2006 10:41 pm


poweroutage
I mean the second last paragraph in your post. here:

Aa. I misread. Apologies.

It may make more sense if you recall that the parametric form of a circle is (r.cos(t),r.sin(t)), while the parameteric form of a hyperbola is (r.cosh(t),r.sinh(t)) [or, rather, half a hyperbola].
poweroutage
So now I don't understand what the rotation in Euclidian coordinates and t constant rotation in Minkowski spacetime is. I understand the whole hyperbola thing and the equations for spacetime.

The rotation matrix in Euclidean coordinates looks like R = [cos T, sin T; -sin T cos T]. In other words, [x';y'] = R[x;y], or explicitly
x' = x cos T + y sin T
y' = y cos T - x sin T

Now, under the spatial Wick rotation x→ix, the Minkowski metric turns into the Euclidean metic, and angle T will be also be imaginary (T→iT). So the transformation for [t;ix]→[t';ix'] will be
t' = t cos(iT) + ix sin(iT)
ix' = ix cos(iT) - t sin(iT).

Applying cos(iT) = cosh T and sin(iT) = i sinh T, we have:
t' = t cosh T - x sinh T
x' = x cosh T - y sinh T, factor of i cancelling here.
In other words, the Minkowski rotation is
[t'] = [ cosh T -sinh T ][ x ]
[x'] = [ -sinh T cosh T ][ t ]

This is the Lorentz transformation. In Euclidean space, the angle a vector [x;y] makes is T = atan(y/x). In Minkowski spacetime, all that is different is that the computation is now hyperbolic: T = atanh(x/t) = atanh(v), if the [t;x] vector represents a velocity (dist/time = x/t). Look up the canonical Lorentz transformation and make the substitution v = tanh T, γ = [1-v²]^{-1/2} = [1-tanh² T]^{-1/2} = [sech² T]^{-1/2} = cosh T. You'll see that it is exactly the same, since -γv = -[tanh T][cosh T] = -sinh T.

How do velocities add? The angles of the velocity vectors add--a rotation by angle V followed by a rotation by angle W is equal to a rotation by angle V+W. The corresponding velocities are tanh of those values: tanh(V+W) = [tanh(V) + tanh(W)]/[1 + tanh(V)tanh(W)] = [v+w]/[1+vw]. This is exactly the canonical velocity addition formula. Its geometrical meaning is a rotation followed by another rotation.

Personally, I prefer the geometrical approach because it emphasizes the spacetime view, and that view makes many so-called paradoxes disappear. (See my response to rugged here.) By the way: I forgot to mention the meaning of spacetime distance. It's the amount of proper time elapsed along a linear path path (i.e., the amount of time a clock going along that path would measure). Thus, the geometrical approach also gives a direct way to measure proper time. No need to figure out what is dilated relative to what; just apply the Minkowski distance formula--spacetime diagrams do it for you!

VorpalNeko
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PostPosted: Wed Jun 28, 2006 1:30 am


Bah, at some point this summer I'm going to get a good book and attempt to fill the GTR hole in my education [I think my special rel. could do with a dust down as well, to be honest]. Vorpal, any recommendations for good texts on GTR?
PostPosted: Wed Jun 28, 2006 2:58 pm


A Lost Iguana
Bah, at some point this summer I'm going to get a good book and attempt to fill the GTR hole in my education [I think my special rel. could do with a dust down as well, to be honest]. Vorpal, any recommendations for good texts on GTR?

I'd recommend "A First Course in General Relativity" by Bernard F. Schutz.
By far the best introductory book.

Friendship coordinator


VorpalNeko
Captain

PostPosted: Wed Jun 28, 2006 6:10 pm


I keep hearing good things about Schutz, but since I don't own it, no comment.
A Lost Iguana
Bah, at some point this summer I'm going to get a good book and attempt to fill the GTR hole in my education [I think my special rel. could do with a dust down as well, to be honest]. Vorpal, any recommendations for good texts on GTR?

The majority of the books I own on GTR and related topics are actually shifted towards the latter (esp. differential geometry), but I'll assume you're more interested in physics. I'm now sure of your current level of mathematics, so I'll simply say this: check out Carroll first, and if it seems too hard, fall back on d'Inverno. If it is clear and you would like to know more, Wald very good and MTW will serve you for years to come. Additionally, try to see if you can get a glimse of Weinberg--that one definietly feels like it's written by a particle physicists for particle physicists.

The first thing to do is to look at this book:
  • Carroll, S.: Spacetime and Geometry: An Introduction to General Relativity. Addison-Wesley, 2004. [www] [gr-qc/9712019].
Not only is it a very good introductory book to GTR, but it is actually available online. It covers a wide variety of topics, including black hole thermodynamics and curved spacetime QFT. Best of all, it's free, which is why I mention it first. Take a look at it to gauge your current level. If Carroll looks like it might give you trouble, I the best remedy for that is:
  • d'Inverno, R.: Introducing Einstein's Relativity. Oxford: Clarendon Press, 1992.
This book begins with essentially nothing--it starts with the Bondi k-calculus approach to STR (the k-factor is actually exp(T), where T is the Minkowski angle as above, making them multiplicative instead of additive); it develops the elementary mathematics needed for GTR in a very clear, although inelegant, way, and then goes on to GTR topics like the Schwarzschild solution, black holes, gravitational waves, and the Friedmann-Lemaître-Robertson-Walker family of cosmological solutions. It does not cover thermodynamics or QFT. Further cons are that the exercises are boring and the mathematics are inelegant. Despite this, d'Inverno is simply the best book for a complete beginner.

On the other hand, if you're fairly experienced in the background mathematics already, a better try might be:
  • Wald, R.: General Relativity. Chicago: University of Chicago Press, 1984.
Wald is one of the better books to learn modern GTR from. It coveres a wide variety of topics, the only conspicuously missing piece being gravitational waves. I think that for serious study, Wald is one of the best.

The Bible:
  • Misner, C.; Thorne, K.; Wheeler, J.: Gravitation. San Francisco: W. H. Freeman and Company, 1973.
If you can afford it (in my experience, it is almost impossible to check it out from libraries--I was once on a waiting list for over half a year before I simply purchased it), this tome will serve you very well. It has almost everything you would need, starting from the basics. My only complaint is that the style doing mathematics seems very inconsistent--perhaps because it was written by three people. MTW does not cover black-hole thermodynamics or curved-spacetime QFT, but covers just about everything else, beginning with STR, in more depth than should be legal. (Except global methods, which is a shame.)

MTW may be a bit overwhelming. I'd recommend shelling out the cash for that one only if you will have frequent contant with GTR in the future. Speaking of global methods...
  • Hawking, S.; Ellis, G.: The Large Scale Structure of Space-Time. Cambridge: Cambridge University Press, 1975.
What MTW lacks in global methods, this book has. It assumes a near-mastery of tensors, however, and draws on many other mathematical topics like topology. You probably won't need it, but I include it here because it is one of my favorites. It is not a textbook, but a monograph.

Since you are in particle physics, you may enjoy the following:
  • Weinberg, S. Gravitation and Cosmology: Principles and Applicatins of The General Theory of Relativity. John Wiley & Sons, 1972.
Weinberg doesn't like geometry in GTR, and consequently I could never get very deep into this book before finding it tiresome. It may be alright for you, given your background in particle physics. One of the focuses of this book is physical experiments, in which it is fairly unique, although overall it is still very theoretical (I'm not sure how you feel about that). It is also the only introductory GTR book I own that covers gravitons in any significant amount of detail. I'd recommend seeing if this book is available at a library or elsewhere first--it is very mathematically demanding, so don't commit unless you're certain!

Finally, the following is a differential geometry book:
  • O'Neill, B.: Semi-Riemannian Geometry. San Diego: Academic Press, 1983
This book is nothing short of geometry of GTR (i.e., semi-Riemannian) done right. It makes all the others' treatments look like mere cookbooks. I don't expect you're interested in the mathematics particularly, but if you are, this book is one of the better ones for GTR.
PostPosted: Thu Jun 29, 2006 1:27 am


Thanks, guys. I'll take a look at the Carroll notes first and see how that goes. It's mainly a case of finding the time to sit down and work through them.

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nonameladyofsins

PostPosted: Thu Jun 29, 2006 9:23 am


ok I understand what the Euclidian and Mikowski rotations are now, mathematically... but (and forgive me if this is somehow inherent in what you've posted) what are they used for? and why do you need them?
PostPosted: Thu Jun 29, 2006 9:49 am


Euclidian rotations are simply rotations of points in space about an angle. Minkowski rotations are another representation of Lorentz transformations. One use of Lorentz boosts [another name for the Lorentz transformation] is converting between the rest frame of a particle and the lab frame [where you are located].

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nonameladyofsins

PostPosted: Thu Jun 29, 2006 10:49 am


A Lost Iguana
Euclidian rotations are simply rotations of points in space about an angle. Minkowski rotations are another representation of Lorentz transformations. One use of Lorentz boosts [another name for the Lorentz transformation] is converting between the rest frame of a particle and the lab frame [where you are located].


ah, very cool. smile
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Astrophysics, Cosmology, and Relativity

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