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 Posted: Wed May 24, 2006 6:06 pm
Fine, have it your way Tosh! scream
*Buys another boxload of pocky and ramen. Holes up in an armoured fort wired with a thousand machine guns, rocketlaunchers and chainsaws and tripwire mines. Starts eating pocky and ramen*
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Posted: Wed May 24, 2006 7:15 pm
Mini's gonna become v. v. big after he finishes eating all that..
Wonder if he'll explode.
o-o
`steals some of Mini's pocky and eats it`
~.:* *:.~
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Posted: Fri May 26, 2006 3:50 pm
Darn that Charlie. =/
-eats pocky-
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Posted: Fri May 26, 2006 5:21 pm
Heh heh, this last page of eating pocky and stealing each other's pocky was quite fun. xd
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Posted: Fri May 26, 2006 5:48 pm
Life Time Supply For Poky To Whoever Fully Explains Heron's Formula. >_>
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Posted: Fri May 26, 2006 5:59 pm
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Posted: Fri May 26, 2006 7:09 pm
I know! I know!
tis a squared + b squared = c squared!
Oh wait.
That's pythagoras.
ninja
Close enough.
Where's my pocky?
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Posted: Fri May 26, 2006 9:05 pm
[...sinfulanjel...]
I know! I know!
tis a squared + b squared = c squared!
Oh wait.
That's pythagoras.
ninja
Close enough.
Where's my pocky?
Close but no cigar. pirate
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Posted: Fri May 26, 2006 9:21 pm
Here's a link to a site that explains Heron's formula: http://mathworld.wolfram.com/HeronsFormula.htmlIt gives the area of the triangle as as the square root of (s(s-a)(s-b)(s-c)) where s is the semiperimeter of a circle, a,b, and c are the sides of a triangle. The relation between s, a, b, and c is given by s=1/2(a+b+c) Heron's proof of this formula is best done using the cosine formula of cos A= b2+c2-a2 over 2bc
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Posted: Sat May 27, 2006 3:52 am
I don't like pocky. And I've never tried the kind of Ramen you guys are talking about.. ninja
*slurps at vanilla frap
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Posted: Sat May 27, 2006 3:59 pm
Minielf Here's a link to a site that explains Heron's formula: http://mathworld.wolfram.com/HeronsFormula.htmlIt gives the area of the triangle as as the square root of (s(s-a)(s-b)(s-c)) where s is the semiperimeter of a circle, a,b, and c are the sides of a triangle. The relation between s, a, b, and c is given by s=1/2(a+b+c) Heron's proof of this formula is best done using the cosine formula of cos A= b2+c2-c2 over 2bc
But wouldn't it just be
Cos A = b2 ((over)) 2bc
Cause +c2-c2 = 0?
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Posted: Sat May 27, 2006 4:55 pm
[...sinfulanjel...] Minielf Here's a link to a site that explains Heron's formula: http://mathworld.wolfram.com/HeronsFormula.htmlIt gives the area of the triangle as as the square root of (s(s-a)(s-b)(s-c)) where s is the semiperimeter of a circle, a,b, and c are the sides of a triangle. The relation between s, a, b, and c is given by s=1/2(a+b+c) Heron's proof of this formula is best done using the cosine formula of cos A= b2+c2-c2 over 2bc
But wouldn't it just be
Cos A = b2 ((over)) 2bc
Cause +c2-c2 = 0?
Oops, that was a spelling mistake. I've edited the formula above. It sthould say b2+c2- a2.
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Posted: Sat May 27, 2006 9:02 pm
Minielf [...sinfulanjel...] Minielf Here's a link to a site that explains Heron's formula: http://mathworld.wolfram.com/HeronsFormula.htmlIt gives the area of the triangle as as the square root of (s(s-a)(s-b)(s-c)) where s is the semiperimeter of a circle, a,b, and c are the sides of a triangle. The relation between s, a, b, and c is given by s=1/2(a+b+c) Heron's proof of this formula is best done using the cosine formula of cos A= b2+c2-c2 over 2bc
But wouldn't it just be
Cos A = b2 ((over)) 2bc
Cause +c2-c2 = 0?
Oops, that was a spelling mistake. I've edited the formula above. It sthould say b2+c2- a2.
Mmkay.
Otherwise I'd be so lost.
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Posted: Sun May 28, 2006 1:05 am
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