Shazzer
GO ME ACING A MATH TEST!
*waves said test around and does a spiffy dance*
If Lucifer were an equation, he would be a parabole. A
french parabole.
He's a series. He's the series: (Sigma)n=0->infinity of (x^(2n))/(2n!) = cos(x)
Jesus is the series (Sigma)n=0->infinity of (x^(2n+1))/((2n+1)!) = sin(x)
I'm being completely serious!
.9 repeating = 1
Here's the proof.
1/9 = (Sigma)n=0->infinity 1/(n+1) = .11111111111111111111111111(repeating)
1 = 9/9 = 9(Sigma)n=0->infinity 1/(n+1) = (Sigma)n=0->infinity 9/(n+1) = .999999999999999(repeating)
Therefore:
.999999999999999(repeating) = 1
Reply
