Carlos Ralfer
Alright folks, got a few things here that I'd like your opinions on.
First one is the exact way travel posts are calculated. As you know, we have travel times up and the current way they are calculated is
1 post per hour. If your trip is taking more than a day, 1 day = 10 posts instead of 24.
Here's the thing though, what to do with the change? Like say you have 30 hours, thats 1 day and 6 hours.
So the question is should we come up with an equation for it or just make you bastards do the extra posts till you hit 48 hours then cut it down to 20 posts.
Dragon has come up with this formula:
Trip time is 13 hours
24 hours = 10 posts
13 hours = x posts
x= ( 13 x 10) / 24 = 5.41 rounded down 5 posts
Not exactly sure how she got the formula but yea, it basically eqates to less posts.
I'm not really feeling the addition of more math to the guild for something like travel posts so I'd rather just have you do the extra posts using the original calculations of 24 hours = 10 posts, 1 hour = 1 post. So that 13 hours used above would be 13 posts.
Lets not forget that you can train/get into random battles during your travel posts.
So gimme feedback
/////////////////////////////////////////////////////////////////
Second thing on the chopping block is monster drops. Lets face it, it's not much of an RPG without monsters/enemies dropping SOMETHING.
So, fairly simple suggestion is this: Each monster will have a group of 3 items they carry. Common, Scarce and Rare. Not all monsters will have an item in each of the catagories but thats the norm.
They will also have an item drop rate.
Each item will have a drop chance based on it's class so the Rare item will obviously be the hardest to get, followed by scarce and then common.
Here's how it would work, When you beat the snot out of the monster, roll 2 100 sided die. The first one is for the item drop rate.
Say you have a goblin who's item drop rate is 25%.What this means is that the goblin has a 25% chance of dropping SOMETHING. So if the first 100D lands on 2-26, then you can count the 2nd dice. If it lands on 27 or higher, then it doesn't drop anything.
Now, if you make it to the 2nd dice, then you take into account the drop chances. So lets say the same goblin has a Common potion, a Scarce Either and a Rare Ultima Weapon (just humor me) The common item has a drop chance of 40%, the Scarce has a drop chance of 20% and the Rare has a drop chance of 5%
What you do for THIS one is put the 40% on the lower part of the dice, 20 on the next set of numbers and 5 on the last section.
So your 2nd 100D would be divded like this:
Roll 1 = fail
Roll 2 - 41 = gain potion
Roll 42 - 62 = gain Either
Roll 62 - 67 = Ultima Weapon
Roll 68 - 99 = No drop
Roll 100 = Get any of the drops you want.
So, does that sound about riht or should I just have the single dice roll?
First one is the exact way travel posts are calculated. As you know, we have travel times up and the current way they are calculated is
1 post per hour. If your trip is taking more than a day, 1 day = 10 posts instead of 24.
Here's the thing though, what to do with the change? Like say you have 30 hours, thats 1 day and 6 hours.
So the question is should we come up with an equation for it or just make you bastards do the extra posts till you hit 48 hours then cut it down to 20 posts.
Dragon has come up with this formula:
Trip time is 13 hours
24 hours = 10 posts
13 hours = x posts
x= ( 13 x 10) / 24 = 5.41 rounded down 5 posts
Not exactly sure how she got the formula but yea, it basically eqates to less posts.
I'm not really feeling the addition of more math to the guild for something like travel posts so I'd rather just have you do the extra posts using the original calculations of 24 hours = 10 posts, 1 hour = 1 post. So that 13 hours used above would be 13 posts.
Lets not forget that you can train/get into random battles during your travel posts.
So gimme feedback
/////////////////////////////////////////////////////////////////
Second thing on the chopping block is monster drops. Lets face it, it's not much of an RPG without monsters/enemies dropping SOMETHING.
So, fairly simple suggestion is this: Each monster will have a group of 3 items they carry. Common, Scarce and Rare. Not all monsters will have an item in each of the catagories but thats the norm.
They will also have an item drop rate.
Each item will have a drop chance based on it's class so the Rare item will obviously be the hardest to get, followed by scarce and then common.
Here's how it would work, When you beat the snot out of the monster, roll 2 100 sided die. The first one is for the item drop rate.
Say you have a goblin who's item drop rate is 25%.What this means is that the goblin has a 25% chance of dropping SOMETHING. So if the first 100D lands on 2-26, then you can count the 2nd dice. If it lands on 27 or higher, then it doesn't drop anything.
Now, if you make it to the 2nd dice, then you take into account the drop chances. So lets say the same goblin has a Common potion, a Scarce Either and a Rare Ultima Weapon (just humor me) The common item has a drop chance of 40%, the Scarce has a drop chance of 20% and the Rare has a drop chance of 5%
What you do for THIS one is put the 40% on the lower part of the dice, 20 on the next set of numbers and 5 on the last section.
So your 2nd 100D would be divded like this:
Roll 1 = fail
Roll 2 - 41 = gain potion
Roll 42 - 62 = gain Either
Roll 62 - 67 = Ultima Weapon
Roll 68 - 99 = No drop
Roll 100 = Get any of the drops you want.
So, does that sound about riht or should I just have the single dice roll?
didnt see this....and i should check more also XD.
but yes the 2 rolls sounds good to me, but one thing have a 100% chance to have like rp drops, meaning if we want we can always take the corpses weapons, armor, or stuff like scrap metal, hides, bomb fragments, stuff the monster is actually made of should always drop...like corpse harvesting.
