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SapphireSara3 Vice Captain
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 Posted: Sun May 25, 2008 8:14 am
Ok, so I'm doing this project in math and I have to find the surface area & volume of a building. It's an irregular octagonal prism & the roof is an irregular octagonal pyramid. I found the surface area by breaking up the shapes and adding them together, but Im stuck on the volume. I know how to find the prism part of it, but how would I find the roof? sweatdrop
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Posted: Sun May 25, 2008 8:31 am
I'll be inviting people now until my math teacher e-mails me back or somebody here can answer. :]
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SapphireSara3 Vice Captain
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Posted: Sun May 25, 2008 9:09 am
Ehhh, not really sure what the question is, but the volume of a pyramid is always a third of the area of the base times the height, or 1/3Bh
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Posted: Sun May 25, 2008 9:17 am
>>
Yeah, I know but now I think it's not even a pyramid. D:
It's like ... I don't even know what it is, actually.
<<
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SapphireSara3 Vice Captain
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Posted: Sun May 25, 2008 9:28 am
Okaaay then.
Wazzit look like?
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Posted: Sun May 25, 2008 2:07 pm
uhm well it is basically an octagonal pyramid but longer.. you know what I mean? Waiit I have a picture! I'll go upload that. sweatdrop Swet here it is. 
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SapphireSara3 Vice Captain
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Nisa the Brown Nose Clown
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Posted: Sun May 25, 2008 3:43 pm
I have no clue but my logical guess is,
s1*s2*s3*s4*s5*s6*s7*s8*h
Thats my guess. Get the measurement of each edge, I think, and use the pathagreom therom(sp?) to get the height.
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Posted: Sun May 25, 2008 3:54 pm
Yeah, I agree with Nisa. Doing that will be the most effective way of finding the measurement. wink
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Nisa the Brown Nose Clown
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Posted: Sun May 25, 2008 3:57 pm
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Posted: Sun May 25, 2008 4:17 pm
Thank you ;D
I think that should work...
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SapphireSara3 Vice Captain
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