# Welcome to Gaia! ::

IRL Genius

Alright, it's a simple question but I suck at chemistry so I can't figure out how to run the numbers to figure this one out. I know it can be figured out using the ideal gas law, but I have no idea how to use that. Help would be appreciated!

I'm trying to figure out what the increase in volume is when boiling mercury and changing it from a liquid to a gas. For the purposes of this, the temperature can be assumed to be right around the boiling point of mercury (356.7 °C).

To clarify, I know that for example water increases in volume to about 1600 times its previous volume when going from a liquid to a gas. I'm trying to figure out what the number is on mercury.

Any help would be great, thank you!

Shameless Heckler

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Primal Conundrum
Alright, it's a simple question but I suck at chemistry so I can't figure out how to run the numbers to figure this one out. I know it can be figured out using the ideal gas law, but I have no idea how to use that. Help would be appreciated!

I'm trying to figure out what the increase in volume is when boiling mercury and changing it from a liquid to a gas. For the purposes of this, the temperature can be assumed to be right around the boiling point of mercury (356.7 °C).

To clarify, I know that for example water increases in volume to about 1600 times its previous volume when going from a liquid to a gas. I'm trying to figure out what the number is on mercury.

Any help would be great, thank you!

Use the gas constant law.

N m^-2 = 1 Pascal

PV = nRT
V = nRT/P = (187.8 g / 200.6 g Hg/mol) (8.314472 m^3 Pa /K mol) (862.7) /
(52995 Pa) = 0.1267 m^3

187.6 g mercury has a volume of 0.1267 m^3 when in vapor form. you can do the math from there to work out the ratio.

IRL Genius

washu_2004
Primal Conundrum
Alright, it's a simple question but I suck at chemistry so I can't figure out how to run the numbers to figure this one out. I know it can be figured out using the ideal gas law, but I have no idea how to use that. Help would be appreciated!

I'm trying to figure out what the increase in volume is when boiling mercury and changing it from a liquid to a gas. For the purposes of this, the temperature can be assumed to be right around the boiling point of mercury (356.7 °C).

To clarify, I know that for example water increases in volume to about 1600 times its previous volume when going from a liquid to a gas. I'm trying to figure out what the number is on mercury.

Any help would be great, thank you!

Use the gas constant law.

N m^-2 = 1 Pascal

PV = nRT
V = nRT/P = (187.8 g / 200.6 g Hg/mol) (8.314472 m^3 Pa /K mol) (862.7) /
(52995 Pa) = 0.1267 m^3

187.6 g mercury has a volume of 0.1267 m^3 when in vapor form. you can do the math from there to work out the ratio.

When you say 0.1267 m^3, does the m stand for meters? Sorry, I'm trash at this stuff.

Assuming that's meters, my numbers show that it expands by roughly ten times in volume, give or take.

Shameless Heckler

• 100
• 100
• 100
Primal Conundrum
washu_2004
Primal Conundrum
Alright, it's a simple question but I suck at chemistry so I can't figure out how to run the numbers to figure this one out. I know it can be figured out using the ideal gas law, but I have no idea how to use that. Help would be appreciated!

I'm trying to figure out what the increase in volume is when boiling mercury and changing it from a liquid to a gas. For the purposes of this, the temperature can be assumed to be right around the boiling point of mercury (356.7 °C).

To clarify, I know that for example water increases in volume to about 1600 times its previous volume when going from a liquid to a gas. I'm trying to figure out what the number is on mercury.

Any help would be great, thank you!

Use the gas constant law.

N m^-2 = 1 Pascal

PV = nRT
V = nRT/P = (187.8 g / 200.6 g Hg/mol) (8.314472 m^3 Pa /K mol) (862.7) /
(52995 Pa) = 0.1267 m^3

187.6 g mercury has a volume of 0.1267 m^3 when in vapor form. you can do the math from there to work out the ratio.

When you say 0.1267 m^3, does the m stand for meters? Sorry, I'm trash at this stuff.

Assuming that's meters, my numbers show that it expands by roughly ten times in volume, give or take.

Yep m^3 is cubic meters.

IRL Genius

washu_2004
Primal Conundrum
washu_2004
Primal Conundrum
Alright, it's a simple question but I suck at chemistry so I can't figure out how to run the numbers to figure this one out. I know it can be figured out using the ideal gas law, but I have no idea how to use that. Help would be appreciated!

I'm trying to figure out what the increase in volume is when boiling mercury and changing it from a liquid to a gas. For the purposes of this, the temperature can be assumed to be right around the boiling point of mercury (356.7 °C).

To clarify, I know that for example water increases in volume to about 1600 times its previous volume when going from a liquid to a gas. I'm trying to figure out what the number is on mercury.

Any help would be great, thank you!

Use the gas constant law.

N m^-2 = 1 Pascal

PV = nRT
V = nRT/P = (187.8 g / 200.6 g Hg/mol) (8.314472 m^3 Pa /K mol) (862.7) /
(52995 Pa) = 0.1267 m^3

187.6 g mercury has a volume of 0.1267 m^3 when in vapor form. you can do the math from there to work out the ratio.

When you say 0.1267 m^3, does the m stand for meters? Sorry, I'm trash at this stuff.

Assuming that's meters, my numbers show that it expands by roughly ten times in volume, give or take.

Yep m^3 is cubic meters.

Cool! Yeah, looks like the conversion ratio is a bit under ten times expansion. I don't need it to be exact, I'm using this for something in some fiction I'm working on and I don't want to be one of *those* writers who does something in flagrant disregard for the actual science of stuff.

Thank you so much for the help with this!