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Riddle Gold Givaway (i found a new riddle)

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franKii924

PostPosted: Sun May 16, 2010 10:25 am


Basic info:
I'll put up one riddle every time some one solves the previous one. The first person to solve it will get 5,000g. If no one has solved it, no one gets the gold.

Rules:
follow guild rules and ToS
be nice
no begging
no advertisement
Post all answers on the thread
i'll only give clues when asked a yes or no question

*****This riddle is pretty hard so 10k+ for the prize, depending on how fast its solved*****

The Riddle:
You have twelve coins. You know that one is fake. The only thing that distinguishes the fake coin from the real coins is that its weight is imperceptibly different. You have a perfectly balanced scale. The scale only tells you which side weighs more than the other side.

What is the smallest number of times you must use the scale in order to always find the fake coin?


Use only the twelve coins themselves and no others, no other weights, no cutting coins, no pencil marks on the scale. etc.

These are modern coins, so the fake coin is not necessarily lighter.

Presume the worst case scenario, and don't hope that you will pick the right coin on the first attempt.


**explain so i know its not a guess**
PostPosted: Sun May 16, 2010 11:18 am


fraNxx924
Basic info:
I'll put up one riddle every week. The first person to solve it will gete 5,000g. If no one has solved it, no one gets the gold.

Rules:
follow guild rules and ToS
be nice
no begging
no advertisement
Post all answers on the thread
i'll only give clues when asked a yes or no question


The Riddle:
There are 5 houses each with a different color. Their owners, each with a unique heritage, drinks a certain type of beverage, smokes a certain brand of cigarette, and keeps a certain variety of pet. None of the owners have the same variety of pet, smoke the same brand of cigarette or drink the same beverage.

Information needed:

* The Brit lives in the red house.
* The Swede keeps dogs as pets.
* The Dane drinks tea.
* Looking from in front, the green house is just to the left of the white house.
* The green house's owner drinks coffee.
* The person who smokes Pall Malls raises birds.
* The owner of the yellow house smokes Dunhill.
* The man living in the center house drinks milk.
* The Norwegian lives in the leftmost house.
* The man who smokes Blends lives next to the one who keeps cats.
* The man who keeps a horse lives next to the man who smokes Dunhill.
* The owner who smokes Bluemasters also drinks beer.
* The German smokes Prince.
* The Norwegian lives next to the blue house.
* The man who smokes Blends has a neighbor who drinks water.

Who owns the pet fish?
the Brit

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PostPosted: Sun May 16, 2010 9:58 pm


i know the answer but i don't need the gold i'll let someone else get it ^^
PostPosted: Mon May 17, 2010 3:57 pm


lili redd redd-no

franKii924


whitechocokitty

PostPosted: Fri May 21, 2010 9:45 pm


franKii924

The Riddle:
There are 5 houses each with a different color. Their owners, each with a unique heritage, drinks a certain type of beverage, smokes a certain brand of cigarette, and keeps a certain variety of pet. None of the owners have the same variety of pet, smoke the same brand of cigarette or drink the same beverage.

Information needed:

* The Brit lives in the red house.
* The Swede keeps dogs as pets.
* The Dane drinks tea.
* Looking from in front, the green house is just to the left of the white house.
* The green house's owner drinks coffee.
* The person who smokes Pall Malls raises birds.
* The owner of the yellow house smokes Dunhill.
* The man living in the center house drinks milk.
* The Norwegian lives in the leftmost house.
* The man who smokes Blends lives next to the one who keeps cats.
* The man who keeps a horse lives next to the man who smokes Dunhill.
* The owner who smokes Bluemasters also drinks beer.
* The German smokes Prince.
* The Norwegian lives next to the blue house.
* The man who smokes Blends has a neighbor who drinks water.

Who owns the pet fish?


Is it the German?
PostPosted: Sun May 23, 2010 10:22 am


yeah its the german

franKii924


whitechocokitty

PostPosted: Sun May 23, 2010 8:32 pm


Really?! Yay! It took me forever to figure it out, I had to draw out a chart and do a bunch of out-loud reasoning to figure it out. I'm so glad it all paid off. 4laugh
PostPosted: Mon May 24, 2010 6:31 pm


haha yeah my friend showed me one like this and i did the same

franKii924


whitechocokitty

PostPosted: Tue May 25, 2010 6:12 pm


Oh, so is there a pattern/formula?
PostPosted: Thu May 27, 2010 2:59 pm


You should do another one!! XD It was fun!

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whitechocokitty

PostPosted: Fri May 28, 2010 12:51 pm


Yes, yes. Like I said, it entertained me for quite a bit of time. 3nodding
PostPosted: Mon Jun 28, 2010 6:07 pm


i think worse case scenario would be 11- you would have to weigh out most the coins until you found one two that were different, then figure out which of those two were different then the rest. Except if it was the last coin then you that's it because the rest are all the same.

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franKii924

PostPosted: Mon Jun 28, 2010 10:06 pm


tigergirl713
i think worse case scenario would be 11- you would have to weigh out most the coins until you found one two that were different, then figure out which of those two were different then the rest. Except if it was the last coin then you that's it because the rest are all the same.


no its a hard one
PostPosted: Wed Jun 30, 2010 4:48 pm


franKii924

The Riddle:
You have twelve coins. You know that one is fake. The only thing that distinguishes the fake coin from the real coins is that its weight is imperceptibly different. You have a perfectly balanced scale. The scale only tells you which side weighs more than the other side.

What is the smallest number of times you must use the scale in order to always find the fake coin?


Use only the twelve coins themselves and no others, no other weights, no cutting coins, no pencil marks on the scale. etc.

These are modern coins, so the fake coin is not necessarily lighter.

Presume the worst case scenario, and don't hope that you will pick the right coin on the first attempt.


**explain so i know its not a guess**


Is it 5 tries? (I'm assuming that it's the worst case scenario with the least number of tries, right?)
Oh boy, this is going to be a LONG explanation.

- Split the 12 coins into 4 groups of 3 coins each.

- SCALE USE #1: Put one of the groups of 3 coins on each side of the scale (That means you're putting 3 coins on each side of the scale, 6 coins total on the scale at one time). In the worse scenario, each side will weigh the same and the fake coin is in one of the groups of 3 that has not been placed on the scale yet. Remove these coins from the scale and set them aside (separate from the other coins that have yet to be weighed); none of these coins are the fake one because these 2 groups of 3 coins each weighed the same.

- SCALE USE #2: Take one of the remaining groups of 3 coins. Put 2 of the 3 coins of that group on the scale (one on each side, 2 coins total on the scale at one time). In the worse case scenario, these coins will weigh the same, which means they are NOT the fake.

- SCALE USE #3: Take one of the coins that you just weighed off the scale (put it in the other pile that you set aside, since you know it's not the fake). Take the third coin of the group (you just weighed the other 2) and put it on the side of the scale that you just removed 1 coin from (remember which side) (you're weighing this coin that you just put on the scale against against a coin that you already know is not the fake). In the worse case scenario, these 2 coins will weigh the same, which means the new one (and the old one, but you already found that out) is NOT the fake coin. This means that one of the 3 coins in the last group (which you have not put on the scale yet) is the fake.

- SCALE USE#4: Take those coins that you just weighed off the scale an put it with those other NOT-fake coins. So, now we're down to 3 coins. Take 2 of these last 3 coins and put one on each side of the scale. In the worse case scenario, these 2 coins will NOT weigh the same. That means that 1 of the coins on the scale IS the fake (which means the third coin that hasn't been put on the scale yet is NOT fake).

- SCALE USE #5: Take one of the coins that is on the scale off the scale (this coin gets it's OWN pile, it might be the fake one) and put the last coin (that you have not put on the scale yet until now) on the side of the scale that is now empty (That means that you have one coin on each side of the scale again, one you just measured and the other one is now being weighed for the first time. YOU HAVE TO REMEMBER WHICH ONE OF THE COINS ON EACH SIDE OF THE SCALE IS THE "OLD" ONE AND WHICH ONE IS THE "NEW" ONE!!!). If the 2 coins that are now on the scale weigh the same on the scale, then the coin that you put into it's own pile is the fake one. If the scale is uneven with the 2 coins that are now on it, then the "OLD" coin is the fake.

Ahh...finally. I'm done explaining. I really hope I'm right.

whitechocokitty

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