Father Knows Best i
[.SamusAran.]
Isn't it speed over time = rate?
And then you can figure it out?
I dunno.
Bad at maths.
Speed over time (s/t) makes an average velocity, get it's derivative and you get instantanious velocity.
But the problem is with that cooresponding value, trying to get when the two trains will "meet" is a dependant of that value. That is the formula that's needed.
Bleh, my calculus is rusty. What's the formula/method for doing derivatives?
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