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 Posted: Mon Feb 28, 2011 9:11 pm
It doesn't look ick on me.
At all.
XD
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Posted: Mon Feb 28, 2011 10:31 pm
DANDii Lions-- Well too much har down thar is ick.
But bald is ick too.
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Posted: Mon Feb 28, 2011 10:42 pm
Alicia Joana DANDii Lions-- Well too much har down thar is ick.
But bald is ick too. p***s talk.
>>
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Posted: Mon Feb 28, 2011 10:44 pm
H2(g) + CO2(g)<-> H20(g) + CO(g)
When H2(g) is mixed with CO2(g) at 2,000K, equilibrium is achieved according to the equation above. In one experiment, the following equilibrium concentrations were measured:
[H2]=0.20 M
[CO2]=0.30 M
[H2O]=[CO]=0.55M
Kc=5.04
Kp=5.04
e)In a different experiment, 0.50 mole of H2(g) is mixed with 0.50 mole of CO2(g) in a 3.0 L reaction vessel at 2,000K. Calculate the equilibrium concentration, in moles/liter, of CO(g) at this temperature.
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Posted: Mon Feb 28, 2011 10:45 pm
SOMEONE HELP ME WITH THIS PROBLEM PLEZZZZZZZZZZ???? 8D
.. I'm studying for a chem test tomorrow.
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Posted: Mon Feb 28, 2011 10:48 pm
The Lady of Nirvana H2(g) + CO2(g)<-> H20(g) + CO(g) When H2(g) is mixed with CO2(g) at 2,000K, equilibrium is achieved according to the equation above. In one experiment, the following equilibrium concentrations were measured: [H2]=0.20 M [CO2]=0.30 M [H2O]=[CO]=0.55M Kc=5.04 Kp=5.04 e)In a different experiment, 0.50 mole of H2(g) is mixed with 0.50 mole of CO2(g) in a 3.0 L reaction vessel at 2,000K. Calculate the equilibrium concentration, in moles/liter, of CO(g) at this temperature. *head deflates*
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Posted: Mon Feb 28, 2011 10:50 pm
Demonxman The Lady of Nirvana H2(g) + CO2(g)<-> H20(g) + CO(g) When H2(g) is mixed with CO2(g) at 2,000K, equilibrium is achieved according to the equation above. In one experiment, the following equilibrium concentrations were measured: [H2]=0.20 M [CO2]=0.30 M [H2O]=[CO]=0.55M Kc=5.04 Kp=5.04 e)In a different experiment, 0.50 mole of H2(g) is mixed with 0.50 mole of CO2(g) in a 3.0 L reaction vessel at 2,000K. Calculate the equilibrium concentration, in moles/liter, of CO(g) at this temperature. *head deflates* Hah thanks for trying though. xD I know you do Molarity for H2 and CO2. But then do you subtract that by .162 (being that it's gonna be .55x.3 from an earlier problem)..? Or do you add it? And you plug it into to the Kc equation right? xD;;
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Posted: Mon Feb 28, 2011 10:51 pm
FFFF.. Equilibrium...
WIFEY.
LEMME FINISH MY MATH HOMEWORK THEN I'LL HELP!
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Posted: Mon Feb 28, 2011 10:53 pm
DANDii Lions-- FFFF.. Equilibrium...
WIFEY.
LEMME FINISH MY MATH HOMEWORK THEN I'LL HELP! Hehe that was my thought when I heard the test was Tuesday. HAHA xD SURE THING. I'MMA SIT HERE AND STARE AT THE PROBLEM UNTIL IT COMES TO ME.
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Posted: Mon Feb 28, 2011 11:00 pm
The Lady of Nirvana DANDii Lions-- FFFF.. Equilibrium...
WIFEY.
LEMME FINISH MY MATH HOMEWORK THEN I'LL HELP! Hehe that was my thought when I heard the test was Tuesday. HAHA xD SURE THING. I'MMA SIT HERE AND STARE AT THE PROBLEM UNTIL IT COMES TO ME. OKAY DONE.
Gimme a moment.
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Posted: Mon Feb 28, 2011 11:00 pm
The Lady of Nirvana DANDii Lions-- FFFF.. Equilibrium...
WIFEY.
LEMME FINISH MY MATH HOMEWORK THEN I'LL HELP! Hehe that was my thought when I heard the test was Tuesday. HAHA xD SURE THING. I'MMA SIT HERE AND STARE AT THE PROBLEM UNTIL IT COMES TO ME. NO WAIT. I GET IT NOW. But my answers are turning out different.. Can someone plug in .5/.3 and tell me what they got?
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Posted: Mon Feb 28, 2011 11:02 pm
The Lady of Nirvana The Lady of Nirvana DANDii Lions-- FFFF.. Equilibrium...
WIFEY.
LEMME FINISH MY MATH HOMEWORK THEN I'LL HELP! Hehe that was my thought when I heard the test was Tuesday. HAHA xD SURE THING. I'MMA SIT HERE AND STARE AT THE PROBLEM UNTIL IT COMES TO ME. NO WAIT. I GET IT NOW. But my answers are turning out different.. Can someone plug in .5/.3 and tell me what they got? NO WAIT. HUMAN ERROR. I GET IT NOW. It's supposed to be 3 not .3. WHEW. Thank god. Nevermind mind wifey. I get it. 8D
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Posted: Mon Feb 28, 2011 11:02 pm
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Posted: Mon Feb 28, 2011 11:05 pm
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Posted: Mon Feb 28, 2011 11:07 pm
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Reply
