Welcome to Gaia! ::

Gaian Tenkaichi Budoukai

Back to Guilds

Gaia's world martial artist tournament that pits the best fighters against one another for the title of Gaia's Best! 

Tags: tenkaichi, budokai, battle, tournament 

Reply Old Threads
OOC Main - There never was a Quarter Final Goto Page: [] [<<] [<<] [<] 1 2 3 ... 1728 1729 1730 1731 1732 1733 ... 3623 3624 3625 3626 [>] [>>] [>>] [»|]

Quick Reply

Enter both words below, separated by a space:

Can't read the text? Click here

Submit

Saphen

PostPosted: Tue Jul 07, 2009 8:26 pm


Ryu Blazer
Kazyan
I think I can help. I remember about half the stuff from Chem last year.
You wouldnt happen to understand Acid-Base equilibrium?
thermal equilibrium-yes. Acid-base equilibrium-no
PostPosted: Tue Jul 07, 2009 8:26 pm


Ryu Blazer
You wouldnt happen to understand Acid-Base equilibrium?


Yep. Ask away.

Kazyan


countgraves

PostPosted: Tue Jul 07, 2009 8:29 pm


Nora Thorsen
All I wanted was something sweet. *sobs*


*swats her Justice paddle at the snakes* I need an adult!

{-pegs her with a rapped caramel and goes back to playing dead- x-x


oh and for referance;
In these rounds folks? There's no sun right? Like charging from the sun would be bogus in this weather; correct?}
PostPosted: Tue Jul 07, 2009 8:29 pm


Kazyan
Ryu Blazer
You wouldnt happen to understand Acid-Base equilibrium?


Yep. Ask away.
How to calculate the Ph of a 0.02M hydrazine solution (H2NNH2) with hydrazine being a weak base. Its Kb= 1.3x10^-6
@Saphen- I know who to ask when I have a question on that then. blaugh

Ryu Blazer


The Haelstrom Fist

PostPosted: Tue Jul 07, 2009 8:30 pm


Nora Thorsen
All I wanted was something sweet. *sobs*


*swats her Justice paddle at the snakes* I need an adult!


I'm 19.

I legally am an adult in this country! biggrin KEEKake-

Also, Darth, when you get a chance, check the first post of my match. I'd venture that's the best representation of Deitric ever.
PostPosted: Tue Jul 07, 2009 8:32 pm


Logs are involved.

Designated Hero


Ryu Blazer

PostPosted: Tue Jul 07, 2009 8:35 pm


I just need to be walked through the problem. Once I am and understand it then Ill be ok. My instructor doesnt do well to represent what was done in his answer sheet. He just throws it down and we are supposed to understand where the numbers came from and why they were used. Thats my biggest issue right now. I see the problem and its answer but I cant put together the middle stuff.
PostPosted: Tue Jul 07, 2009 8:38 pm


{Somebody answer me?...I dun care how much you hate the turnip; That's right right?

Charging from the sun round two is bogus at best-

Somebody point at me or something; I need confirmation. XD}

countgraves


Kazyan

PostPosted: Tue Jul 07, 2009 8:39 pm


Ryu Blazer
Kazyan
Ryu Blazer
You wouldnt happen to understand Acid-Base equilibrium?


Yep. Ask away.
How to calculate the Ph of a 0.02M hydrazine solution (H2NNH2) with hydrazine being a weak base. Its Kb= 1.3x10^-6
@Saphen- I know who to ask when I have a question on that then. blaugh


*brushes up on molarity*

Uh...-log10(1.3x10^-6) would be the Ph of 1.0 M, one mole per liter...so, 0.02 M is one mole per 50 liters. Uh.

*calculates*

I really don't think I did this right, but, that log value would get close to 7. The calculator said the value was -5.88, so get rid of the minus sign for the pH to get 5.88. 7 - 5.88 = 1.12; 1.12 / 50 =~ 0.02, 7 + 0.02 =~ 7.02. (Those steps cut the distance between 5.88 and 7 down by a factor of 50)

Like I said, I really don't think I did it right, but 7.02.
PostPosted: Tue Jul 07, 2009 8:41 pm


My birthday's in two days. You all should bring me cake and presents.

Nora Thorsen


Ryu Blazer

PostPosted: Tue Jul 07, 2009 8:42 pm


Kazyan
Ryu Blazer
Kazyan
Ryu Blazer
You wouldnt happen to understand Acid-Base equilibrium?


Yep. Ask away.
How to calculate the Ph of a 0.02M hydrazine solution (H2NNH2) with hydrazine being a weak base. Its Kb= 1.3x10^-6
@Saphen- I know who to ask when I have a question on that then. blaugh


*brushes up on molarity*

Uh...-log10(1.3x10^-6) would be the Ph of 1.0 M, one mole per liter...so, 0.02 M is one mole per 50 liters. Uh.

*calculates*

I really don't think I did this right, but, that log value would get close to 7. The calculator said the value was -5.88, so get rid of the minus sign for the pH to get 5.88. 7 - 5.88 = 1.12; 1.12 / 50 =~ 0.02, 7 + 0.02 =~ 7.02. (Those steps cut the distance between 5.88 and 7 down by a factor of 50)

Like I said, I really don't think I did it right, but 7.02.
The answer is 10.21 for the ph. Again my main issue it im not understanding how to even start the problem because of how he writes this s**t. Its ticking me off and the test is in the morning. -sigh- Thank you for the help though.
PostPosted: Tue Jul 07, 2009 8:44 pm


If you're really stuck, Google and Wikipedia are better than a random dude on the internet. sweatdrop

Kazyan


Ryu Blazer

PostPosted: Tue Jul 07, 2009 8:46 pm


Im lazy. sweatdrop
PostPosted: Tue Jul 07, 2009 8:49 pm


Okay then...try this.

Kazyan


Nightsnow

PostPosted: Tue Jul 07, 2009 8:52 pm


...I'm twenty.
Nonetheless - HOSHI - Omi's younger than me by a year?!

o3o

Also - THE CAKE IS A LIE! scream

Have some cupcakes instead. >3>
Reply
Old Threads

Goto Page: [] [<<] [<<] [<] 1 2 3 ... 1728 1729 1730 1731 1732 1733 ... 3623 3624 3625 3626 [>] [>>] [>>] [»|]
 
Manage Your Items
Other Stuff
Get GCash
Offers
Get Items
More Items
Where Everyone Hangs Out
Other Community Areas
Virtual Spaces
Fun Stuff
Gaia's Games
Mini-Games
Play with GCash
Play with Platinum