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Ahoy. I love math. Do you?

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Trellioz

Report | 02/22/2011 4:18 pm

Trellioz


We just got through the fundamental theorem and integration via substitution, the only thing left based off the syllabus (unless I missed something) would be applications thereof.
Trellioz

Report | 02/21/2011 9:18 pm

Trellioz


DUDE BRO. I kinda want some semi-challenging to insanely challenging Calculus stuff just to get me prepped for testing in May. Think you can hook me up?
iiMenthaa

Report | 12/25/2010 7:34 pm

iiMenthaa

Your sig is easy.
It equals fish.
kthxbaii
AnatidaeanAvenger

Report | 10/12/2010 7:25 pm

AnatidaeanAvenger

About the sig, I think it's zero.
http://i247.photobucket.com/albums/gg122/evilchibiduck/sigproblem.png
If Imdoinitrite xd
gleedemon

Report | 09/26/2010 10:09 am

gleedemon

xavi, i've been meaning to get in touch with you via facebook. D:
i know we don't text much, but i am now without a phone, so. yeah.
anyway. come back to florida.
kthxbye. <3
Celestial Luminosity

Report | 09/04/2010 1:15 am

Celestial Luminosity

♥ Shot in the dark -.-
2.577878
Have fun adding me to your "got it wrong" list xP;;
I now remember why I disliked calculus
By the way I <3 Yu-gi-ohUser Image
jestingrabbit

Report | 08/27/2010 4:17 pm

jestingrabbit

The answer to you sig is pi/e. Firstly, you can consolidate all the integrals into the integral from -inf to +inf of cos(x)/(1+x^2). Then I use the fact that exp(ix) = cos(x) + isin(x) and note that it'll be the real part of the integral over the real line of exp(ix)/(1+x^2). From there, do the contour integral around a half circle and diameter, where the diameter is from -R to R on the real line, and the half circle is going from R to -R anti clockwise. The circular part of the integral is bounded in modulus by 1/R. Taking the limit as R goes to infinity, you get the fact that the answer is just the real part of the residue. Not much more effort and you realise that the residue is pi/e. Fin.
Trissana

Report | 08/19/2010 12:41 am

Trissana

I believe the answer to your sig is 0
negative infinity plus infinity is zero.
Keppay

Report | 07/13/2010 9:54 pm

Keppay

About your sig... Isn't it just infinity? Add from zero to infinity.... which is essentially infinity... times by anything, add something, it's still infinity...?
Master Sun Wukong

Report | 05/27/2010 7:33 pm

Master Sun Wukong

is that right?

well i i used up my attempt. to be honest i've already finished my degree's junior math requirements already so i haven't really touched calc since

i'll be sure to suggest this to my friend who's a math major though

now if you'll excuse me, i'm off to play a children's card game...IN CANADA

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