Panjandrum
(?)Community Member
- Posted: Thu, 09 Dec 2004 03:30:05 +0000
GRAR. I've got a hyuge exam on em soon, and I need help.
I thought I had a good enough idea of what I was doing, until I did an online activity..which...totally put my perspective at a slant.
See, here's my problem.
Ethane
C2H6 + O2 > CO2 + H20
C:2 C: 1
H:6 H: 2
O:2 O: 3
And then I start to balance.. (green spaces being where I put my numbers)
| | C2H6 + | | O2 > | | CO2 +| | H20
I first make 2 C in the second C box..
| | C2H6 + | | O2 > | 2 | CO2 +| | H20
So now:
C:2 C: 2
H:6 H: 2
O:2 O: 4
..Right? Now's where I'm beginning to be not so sure. When Oxygen is at two, it'd now be four, right?
So now I..
| | C2H6 + | 2 | O2 > | 2 | CO2 +| | H20
So now:
C:2 C: 2
H:6 H: 2
O:4 O: 4
Double the first Oxygen so now it is now also four! That's balanced..right?
sad 'Cause I thought at the end of these excercises they were supposed to be the exact same on both sides but on the online thingy (http://www.wfu.edu/~ylwong/balanceeq/combust.html) it would 'solve' equations with answers that had different numbers on each.
I'll try to finish this one, though..
I'll make the second Hydrogen multiply by three..
| | C2H6 + | 2 | O2 > | 2 | CO2 +| 3 | H20
So now the second Oxygen also changes?:
C:2 C: 2
H:6 H: 6
O:4 O: 4
........
????
Help please! gonk
I thought I had a good enough idea of what I was doing, until I did an online activity..which...totally put my perspective at a slant.
See, here's my problem.
Ethane
C2H6 + O2 > CO2 + H20
C:2 C: 1
H:6 H: 2
O:2 O: 3
And then I start to balance.. (green spaces being where I put my numbers)
| | C2H6 + | | O2 > | | CO2 +| | H20
I first make 2 C in the second C box..
| | C2H6 + | | O2 > | 2 | CO2 +| | H20
So now:
C:2 C: 2
H:6 H: 2
O:2 O: 4
..Right? Now's where I'm beginning to be not so sure. When Oxygen is at two, it'd now be four, right?
So now I..
| | C2H6 + | 2 | O2 > | 2 | CO2 +| | H20
So now:
C:2 C: 2
H:6 H: 2
O:4 O: 4
Double the first Oxygen so now it is now also four! That's balanced..right?
sad 'Cause I thought at the end of these excercises they were supposed to be the exact same on both sides but on the online thingy (http://www.wfu.edu/~ylwong/balanceeq/combust.html) it would 'solve' equations with answers that had different numbers on each.
I'll try to finish this one, though..
I'll make the second Hydrogen multiply by three..
| | C2H6 + | 2 | O2 > | 2 | CO2 +| 3 | H20
So now the second Oxygen also changes?:
C:2 C: 2
H:6 H: 6
O:4 O: 4
........
????
Help please! gonk