二世画店Two Worlds Artshop!- open for RL comm

What's the ultimate art tool?

A Photosop + Cintiq Tablet (yummy)	40.6%	[ 28 ]
Technical pens	5.8%	[ 4 ]
2B pencils	15.9%	[ 11 ]
My own hands! O_O	37.7%	[ 26 ]
Total Votes:			[ 69 ]

[Bai Hikari Tsubasa]

3nodding

[Zupu]

Bai Hikari Tsubasa

3nodding

.....looooollllll...... sigh.... comm comm anyone? comm comm? comm comm?

[Bai Hikari Tsubasa]

comm come

[Zupu]

I gotta figure out a better way to deal with the carbon fibers.... at first I thought the real trouble of carbon dust is during sanding, and I've got a solution for that.... but when cutting, I see these little puffs coming off, and it's just like NOoooo.

Irony is the sanding part is actually ok, because that would be carbon particles that don't do that much hard. It's the tiny tiny fibers that kills....

[Bai Hikari Tsubasa]

But you weren't suppose to deal with carabon fiber in the first place no?

here's another ques:

a ball of mass 0.1 kg is dropped from a height of 2.0 m onto a hard surface. It rebounds to a height of 1.5m and it is in contact with the surface for 0.05s, find the speed with which it leaves the surface.

[Zupu]

Bai Hikari Tsubasa

But you weren't suppose to deal with carabon fiber in the first place no?

here's another ques:

a ball of mass 0.1 kg is dropped from a height of 2.0 m onto a hard surface. It rebounds to a height of 1.5m and it is in contact with the surface for 0.05s, find the speed with which it leaves the surface.

well... I guess the answer is: you're supposed to deal with things like carbon construction in a proper workshop, not your bedroom... but heck, who have that space luxury...

You can ignore every it tells you, and just use normal equations to find how much ANYTHING needs to be flying upwards to hit zero-velocity after 1.5m vertically.

[Bai Hikari Tsubasa]

Ah, I see 3nodding lol you don't have the space eh...

ok, found the answer biggrin
Next ques:

an object of weight 50N is suspended vertically by two strings (forming a v shape). the strings are of he same length and the angles between them is 60 degree. calculate tension of string

[Zupu]

Bai Hikari Tsubasa

Ah, I see 3nodding lol you don't have the space eh...

ok, found the answer biggrin
Next ques:

an object of weight 50N is suspended vertically by two strings (forming a v shape). the strings are of he same length and the angles between them is 60 degree. calculate tension of string

Draw a Free Body Diagram. Three forces on the object: 50N vertically down, and the two strings diagonally upwards. The vertical components of the two string need to add up to 50N. To the vertical component of each string is 25N. From that, is sin-1 or something to find the hypotenuse component.

[Bai Hikari Tsubasa]

wait, when you say the vertical component, do you mean the opposite is 25N or the adjacent? xD

[Zupu]

Bai Hikari Tsubasa

wait, when you say the vertical component, do you mean the opposite is 25N or the adjacent? xD

I guess that depends on how you look at it, how you draw your "triangle"... the vertical is vertical lah.

[Bai Hikari Tsubasa]

Zupu

Bai Hikari Tsubasa

wait, when you say the vertical component, do you mean the opposite is 25N or the adjacent? xD

I guess that depends on how you look at it, how you draw your "triangle"... the vertical is vertical lah.

okok

although they actually gave us a diagram

[Zupu]

Bai Hikari Tsubasa

Zupu

Bai Hikari Tsubasa

wait, when you say the vertical component, do you mean the opposite is 25N or the adjacent? xD

I guess that depends on how you look at it, how you draw your "triangle"... the vertical is vertical lah.

okok

although they actually gave us a diagram

oh.... then follow their triangle.... Dunno what diagram they give, but usually you always draw your own diagram again... ALWAYS DRAW YOUR F.B.D. or marks will be taken off.

[Bai Hikari Tsubasa]

yeah, they actually expect us to draw our own's xD

hn....power output of cara.....

data: car travels along a level road at speed of 25 m s^-1
fuel consumption : 0.2 L km^-1
Calorific value (what in the world is that!?) of the fuel is 5.0*10^6 J L^-1
Engine efficiency 50%

a. at what rate does the engine consume fuel
b. at what rate does the fuel supply energy
c. what is the power output of the engine?
d. How much of the power is used to overcome the frictional forces acting on the car
e. what is the avg frictional force acting on the car

ugh...I hate chain reaction question because it always involve you solving the first one first, and if you can't, you are dead <.<

[Zupu]

Bai Hikari Tsubasa

yeah, they actually expect us to draw our own's xD

hn....power output of cara.....

data: car travels along a level road at speed of 25 m s^-1
fuel consumption : 0.2 L km^-1
Calorific value (what in the world is that!?) of the fuel is 5.0*10^6 J L^-1
Engine efficiency 50%

a. at what rate does the engine consume fuel
b. at what rate does the fuel supply energy
c. what is the power output of the engine?
d. How much of the power is used to overcome the frictional forces acting on the car
e. what is the avg frictional force acting on the car

ugh...I hate chain reaction question because it always involve you solving the first one first, and if you can't, you are dead <.<

Ooh, are we finally at heat?
Calorific value should just be how much energy there is in the fuel.

A) so 25m/s = 90km/hr = 0.025km/s... so consumption = 0.2 L/km * 0.025km/s = 0.005L/s.
B) 0.005L/s * 5000kJ/L = 25kJ/s
C) 25kJ/s *50% = 12.5kW
D) .... well... that depends on how much coeff of fric is..... I guess the prob assume the 50% wasted is wasted on fric.... but not necessarily so.
E) ? Coeff of fric?

When you ask me these probs, is it just asking me, or are these probs you dunno how to solve?

[Bai Hikari Tsubasa]

Zupu

Bai Hikari Tsubasa

yeah, they actually expect us to draw our own's xD

hn....power output of cara.....

data: car travels along a level road at speed of 25 m s^-1
fuel consumption : 0.2 L km^-1
Calorific value (what in the world is that!?) of the fuel is 5.0*10^6 J L^-1
Engine efficiency 50%

a. at what rate does the engine consume fuel
b. at what rate does the fuel supply energy
c. what is the power output of the engine?
d. How much of the power is used to overcome the frictional forces acting on the car
e. what is the avg frictional force acting on the car

ugh...I hate chain reaction question because it always involve you solving the first one first, and if you can't, you are dead <.<

Ooh, are we finally at heat?
Calorific value should just be how much energy there is in the fuel.

A) so 25m/s = 90km/hr = 0.025km/s... so consumption = 0.2 L/km * 0.025km/s = 0.005L/s.
B) 0.005L/s * 5000kJ/L = 25kJ/s
C) 25kJ/s *50% = 12.5kW
D) .... well... that depends on how much coeff of fric is..... I guess the prob assume the 50% wasted is wasted on fric.... but not necessarily so.
E) ? Coeff of fric?

When you ask me these probs, is it just asking me, or are these probs you dunno how to solve?

c is 50 though .__.

well, those are the questions that I can't solve T^T quite a lot no? although I can still solve half of it xD